| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.03 |
| Score | 0% | 61% |
If AD = 25 and BD = 23, AB = ?
| 6 | |
| 2 | |
| 4 | |
| 7 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDSimplify (8a)(9ab) - (2a2)(2b).
| 68a2b | |
| 76ab2 | |
| 76a2b | |
| 68ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(8a)(9ab) - (2a2)(2b)
(8 x 9)(a x a x b) - (2 x 2)(a2 x b)
(72)(a1+1 x b) - (4)(a2b)
72a2b - 4a2b
68a2b
If c = -4 and x = -9, what is the value of 5c(c - x)?
| 135 | |
| 30 | |
| 108 | |
| -100 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
5c(c - x)
5(-4)(-4 + 9)
5(-4)(5)
(-20)(5)
-100
Solve for z:
-z + 2 < \( \frac{z}{4} \)
| z < -4\(\frac{4}{17}\) | |
| z < -\(\frac{7}{19}\) | |
| z < -2\(\frac{1}{13}\) | |
| z < 1\(\frac{3}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-z + 2 < \( \frac{z}{4} \)
4 x (-z + 2) < z
(4 x -z) + (4 x 2) < z
-4z + 8 < z
-4z + 8 - z < 0
-4z - z < -8
-5z < -8
z < \( \frac{-8}{-5} \)
z < 1\(\frac{3}{5}\)
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
|
4π r2 |
|
2(π r2) + 2π rh |
|
π r2h2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.