When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + 4c = -3c - 8x + 4 for c in terms of x.
| -\(\frac{3}{11}\)x + \(\frac{1}{11}\) | |
| \(\frac{14}{15}\)x + \(\frac{1}{3}\) | |
| -\(\frac{2}{13}\)x + \(\frac{8}{13}\) | |
| -2\(\frac{2}{5}\)x + \(\frac{4}{5}\) |