ASVAB Math Knowledge Practice Test 125310

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c + c = -4c + 5y - 4 for c in terms of y.

\(\frac{2}{5}\)y - \(\frac{2}{5}\)
y - 1
-\(\frac{1}{2}\)y + \(\frac{1}{10}\)
-\(\frac{1}{7}\)y - \(\frac{5}{7}\)