| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.30 |
| Score | 0% | 66% |
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
|
vertical, supplementary |
|
obtuse, acute |
|
acute, obtuse |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
If angle a = 25° and angle b = 61° what is the length of angle c?
| 94° | |
| 70° | |
| 57° | |
| 97° |
The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 25° - 61° = 94°
Solve for x:
-7x + 2 < -7 + 5x
| x < -\(\frac{1}{3}\) | |
| x < \(\frac{3}{7}\) | |
| x < \(\frac{3}{4}\) | |
| x < -6 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-7x + 2 < -7 + 5x
-7x < -7 + 5x - 2
-7x - 5x < -7 - 2
-12x < -9
x < \( \frac{-9}{-12} \)
x < \(\frac{3}{4}\)
If the area of this square is 1, what is the length of one of the diagonals?
| 2\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)
If AD = 29 and BD = 26, AB = ?
| 8 | |
| 13 | |
| 3 | |
| 15 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD