When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 3c = 6c - 5y - 2 for c in terms of y.
| -4y - 1 | |
| y + \(\frac{2}{3}\) | |
| 3\(\frac{1}{2}\)y - 4\(\frac{1}{2}\) | |
| \(\frac{1}{2}\)y + 4 |