When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c - 8c = 5c + 2x - 5 for c in terms of x.
| 5\(\frac{1}{3}\)x + 3 | |
| -\(\frac{2}{5}\)x - 1\(\frac{2}{5}\) | |
| -x + \(\frac{1}{2}\) | |
| \(\frac{2}{5}\)x + \(\frac{3}{5}\) |