When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c - 2c = 3c + 3z + 9 for c in terms of z.
| 1\(\frac{1}{3}\)z - \(\frac{8}{9}\) | |
| 2\(\frac{1}{2}\)z + 4\(\frac{1}{2}\) | |
| 4z - 3 | |
| -15z + 1 |