ASVAB Math Knowledge Practice Test 129098 Results

Your Results Global Average
Questions 5 5
Correct 0 3.71
Score 0% 74%

Review

1

If the area of this square is 16, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
\( \sqrt{2} \)
5\( \sqrt{2} \)
4\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)


2

If a = 4, b = 5, c = 2, and d = 6, what is the perimeter of this quadrilateral?

88% Answer Correctly
16
5
17
25

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 4 + 5 + 2 + 6
p = 17


3

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

83% Answer Correctly

Inside

First

Odd

Last


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.


4

Simplify (y - 2)(y - 1)

63% Answer Correctly
y2 + 3y + 2
y2 - 3y + 2
y2 - y - 2
y2 + y - 2

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y - 2)(y - 1)
(y x y) + (y x -1) + (-2 x y) + (-2 x -1)
y2 - y - 2y + 2
y2 - 3y + 2


5

If a = 2 and z = -2, what is the value of -7a(a - z)?

68% Answer Correctly
-56
0
-60
72

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

-7a(a - z)
-7(2)(2 + 2)
-7(2)(4)
(-14)(4)
-56