ASVAB Math Knowledge Practice Test 129912

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4b - 3b = -2b + 5z + 1 for b in terms of z.

-4z - \(\frac{1}{2}\)
\(\frac{1}{2}\)z - \(\frac{5}{14}\)
z - \(\frac{1}{2}\)
3z + 3