ASVAB Math Knowledge Practice Test 130793

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3c - 5c = 5c + 7z + 5 for c in terms of z.

-4\(\frac{1}{2}\)z + 4\(\frac{1}{2}\)
z - 1\(\frac{1}{5}\)
-1\(\frac{1}{2}\)z - \(\frac{5}{8}\)
\(\frac{1}{3}\)z - \(\frac{2}{3}\)