| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.96 |
| Score | 0% | 59% |
If angle a = 43° and angle b = 55° what is the length of angle d?
| 137° | |
| 133° | |
| 128° | |
| 147° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 43° - 55° = 82°
So, d° = 55° + 82° = 137°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 43° = 137°
Breaking apart a quadratic expression into a pair of binomials is called:
factoring |
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squaring |
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normalizing |
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deconstructing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Solve for a:
4a - 4 < \( \frac{a}{-1} \)
| a < \(\frac{16}{71}\) | |
| a < -\(\frac{12}{55}\) | |
| a < \(\frac{4}{5}\) | |
| a < -1\(\frac{17}{28}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
4a - 4 < \( \frac{a}{-1} \)
-1 x (4a - 4) < a
(-1 x 4a) + (-1 x -4) < a
-4a + 4 < a
-4a + 4 - a < 0
-4a - a < -4
-5a < -4
a < \( \frac{-4}{-5} \)
a < \(\frac{4}{5}\)
Simplify (8a)(3ab) - (7a2)(9b).
| 39ab2 | |
| 176a2b | |
| 176ab2 | |
| -39a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(8a)(3ab) - (7a2)(9b)
(8 x 3)(a x a x b) - (7 x 9)(a2 x b)
(24)(a1+1 x b) - (63)(a2b)
24a2b - 63a2b
-39a2b
If the base of this triangle is 5 and the height is 7, what is the area?
| 17\(\frac{1}{2}\) | |
| 35 | |
| 67\(\frac{1}{2}\) | |
| 56 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 5 x 7 = \( \frac{35}{2} \) = 17\(\frac{1}{2}\)