ASVAB Math Knowledge Practice Test 131012

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2a + 6a = -6a + 6x + 8 for a in terms of x.

x + 1
\(\frac{11}{14}\)x + \(\frac{5}{14}\)
x + \(\frac{1}{4}\)
-\(\frac{6}{7}\)x + \(\frac{3}{14}\)