| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.86 |
| Score | 0% | 57% |
A quadrilateral is a shape with __________ sides.
3 |
|
5 |
|
4 |
|
2 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
Solve for c:
-6c + 1 > -9 - 7c
| c > -10 | |
| c > -\(\frac{3}{4}\) | |
| c > -\(\frac{6}{7}\) | |
| c > \(\frac{4}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-6c + 1 > -9 - 7c
-6c > -9 - 7c - 1
-6c + 7c > -9 - 1
c > -10
Solve -6a + 6a = 5a - 4x + 6 for a in terms of x.
| 1\(\frac{4}{5}\)x - \(\frac{4}{5}\) | |
| -\(\frac{7}{9}\)x - 1 | |
| \(\frac{10}{11}\)x - \(\frac{6}{11}\) | |
| x + 3 |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-6a + 6x = 5a - 4x + 6
-6a = 5a - 4x + 6 - 6x
-6a - 5a = -4x + 6 - 6x
-11a = -10x + 6
a = \( \frac{-10x + 6}{-11} \)
a = \( \frac{-10x}{-11} \) + \( \frac{6}{-11} \)
a = \(\frac{10}{11}\)x - \(\frac{6}{11}\)
The dimensions of this cube are height (h) = 3, length (l) = 7, and width (w) = 7. What is the surface area?
| 92 | |
| 160 | |
| 350 | |
| 182 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 7 x 7) + (2 x 7 x 3) + (2 x 7 x 3)
sa = (98) + (42) + (42)
sa = 182
Which types of triangles will always have at least two sides of equal length?
equilateral, isosceles and right |
|
isosceles and right |
|
equilateral and isosceles |
|
equilateral and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.