When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6c - 8c = -5c + 2z - 1 for c in terms of z.
| 6z + 5 | |
| -\(\frac{1}{5}\)z - \(\frac{3}{5}\) | |
| -10z + 1 | |
| 3z + 6 |