To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

2c - 9 = \( \frac{c}{-6} \)
-6 x (2c - 9) = c
(-6 x 2c) + (-6 x -9) = c
-12c + 54 = c
-12c + 54 - c = 0
-12c - c = -54
-13c = -54
c = \( \frac{-54}{-13} \)
c = 4\(\frac{2}{13}\)

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

3a x 2b = (3 x 2) (a x b) = 6ab

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c² - 14c + 49 = 0
(c - 7)(c - 7) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, (c - 7) must equal zero:

If (c - 7) = 0, c must equal 7

So the solution is that c = 7

You need to find the value of a so solve the first equation in terms of y:

+ y = -5
y = -5 +

then substitute the result (-5 - 0a) into the second equation:

-a + 1(-5 + ) = -8
-a + (1 x -5) + (1 x ) = -8
-a - 5 + = -8
-a + = -8 + 5
-a = -3
a = \( \frac{-3}{-1} \)
a = 3