| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.43 |
| Score | 0% | 49% |
The dimensions of this trapezoid are a = 5, b = 5, c = 8, d = 6, and h = 4. What is the area?
| 22 | |
| 13 | |
| 16 | |
| 17 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(5 + 6)(4)
a = ½(11)(4)
a = ½(44) = \( \frac{44}{2} \)
a = 22
Solve for b:
-6b + 3 < \( \frac{b}{-2} \)
| b < \(\frac{4}{7}\) | |
| b < 4\(\frac{3}{8}\) | |
| b < -\(\frac{8}{15}\) | |
| b < \(\frac{6}{11}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-6b + 3 < \( \frac{b}{-2} \)
-2 x (-6b + 3) < b
(-2 x -6b) + (-2 x 3) < b
12b - 6 < b
12b - 6 - b < 0
12b - b < 6
11b < 6
b < \( \frac{6}{11} \)
b < \(\frac{6}{11}\)
Solve for a:
a2 + 18a + 41 = 4a - 4
| 1 or -7 | |
| 7 or -1 | |
| -5 or -9 | |
| 1 or -8 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
a2 + 18a + 41 = 4a - 4
a2 + 18a + 41 + 4 = 4a
a2 + 18a - 4a + 45 = 0
a2 + 14a + 45 = 0
Next, factor the quadratic equation:
a2 + 14a + 45 = 0
(a + 5)(a + 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (a + 5) or (a + 9) must equal zero:
If (a + 5) = 0, a must equal -5
If (a + 9) = 0, a must equal -9
So the solution is that a = -5 or -9
If the length of AB equals the length of BD, point B __________ this line segment.
bisects |
|
trisects |
|
intersects |
|
midpoints |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
Solve for x:
6x - 4 > -6 - 4x
| x > -1\(\frac{1}{5}\) | |
| x > 2 | |
| x > -\(\frac{1}{5}\) | |
| x > -\(\frac{1}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
6x - 4 > -6 - 4x
6x > -6 - 4x + 4
6x + 4x > -6 + 4
10x > -2
x > \( \frac{-2}{10} \)
x > -\(\frac{1}{5}\)