ASVAB Math Knowledge Practice Test 133761 Results

Your Results Global Average
Questions 5 5
Correct 0 2.43
Score 0% 49%

Review

1

The dimensions of this trapezoid are a = 5, b = 5, c = 8, d = 6, and h = 4. What is the area?

51% Answer Correctly
22
13
16
17

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(5 + 6)(4)
a = ½(11)(4)
a = ½(44) = \( \frac{44}{2} \)
a = 22


2

Solve for b:
-6b + 3 < \( \frac{b}{-2} \)

44% Answer Correctly
b < \(\frac{4}{7}\)
b < 4\(\frac{3}{8}\)
b < -\(\frac{8}{15}\)
b < \(\frac{6}{11}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-6b + 3 < \( \frac{b}{-2} \)
-2 x (-6b + 3) < b
(-2 x -6b) + (-2 x 3) < b
12b - 6 < b
12b - 6 - b < 0
12b - b < 6
11b < 6
b < \( \frac{6}{11} \)
b < \(\frac{6}{11}\)


3

Solve for a:
a2 + 18a + 41 = 4a - 4

48% Answer Correctly
1 or -7
7 or -1
-5 or -9
1 or -8

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

a2 + 18a + 41 = 4a - 4
a2 + 18a + 41 + 4 = 4a
a2 + 18a - 4a + 45 = 0
a2 + 14a + 45 = 0

Next, factor the quadratic equation:

a2 + 14a + 45 = 0
(a + 5)(a + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (a + 5) or (a + 9) must equal zero:

If (a + 5) = 0, a must equal -5
If (a + 9) = 0, a must equal -9

So the solution is that a = -5 or -9


4

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

bisects

trisects

intersects

midpoints


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


5

Solve for x:
6x - 4 > -6 - 4x

55% Answer Correctly
x > -1\(\frac{1}{5}\)
x > 2
x > -\(\frac{1}{5}\)
x > -\(\frac{1}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

6x - 4 > -6 - 4x
6x > -6 - 4x + 4
6x + 4x > -6 + 4
10x > -2
x > \( \frac{-2}{10} \)
x > -\(\frac{1}{5}\)