When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6a + 2a = 4a + 8y - 3 for a in terms of y.
| -1\(\frac{1}{2}\)y - \(\frac{1}{4}\) | |
| -\(\frac{1}{2}\)y + \(\frac{5}{6}\) | |
| 3y - 1\(\frac{1}{2}\) | |
| -3\(\frac{1}{2}\)y + 2 |