When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6b + 2b = 4b + 8z - 3 for b in terms of z.
| -1\(\frac{1}{2}\)z - \(\frac{1}{4}\) | |
| -\(\frac{1}{2}\)z + \(\frac{5}{6}\) | |
| 3z - 1\(\frac{1}{2}\) | |
| -3\(\frac{1}{2}\)z + 2 |