| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
If a = c = 1, b = d = 9, what is the area of this rectangle?
| 6 | |
| 49 | |
| 14 | |
| 9 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 1 x 9
a = 9
Solve for b:
6b + 8 = \( \frac{b}{3} \)
| -\(\frac{12}{13}\) | |
| -\(\frac{8}{11}\) | |
| -1\(\frac{7}{17}\) | |
| \(\frac{9}{17}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
6b + 8 = \( \frac{b}{3} \)
3 x (6b + 8) = b
(3 x 6b) + (3 x 8) = b
18b + 24 = b
18b + 24 - b = 0
18b - b = -24
17b = -24
b = \( \frac{-24}{17} \)
b = -1\(\frac{7}{17}\)
The formula for the area of a circle is which of the following?
a = π d2 |
|
a = π d |
|
a = π r |
|
a = π r2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Solve -2a + 5a = -8a - 3z - 9 for a in terms of z.
| \(\frac{1}{7}\)z - 1 | |
| -13z - 4 | |
| -1\(\frac{1}{3}\)z - 1\(\frac{1}{2}\) | |
| \(\frac{1}{8}\)z + 1\(\frac{1}{8}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-2a + 5z = -8a - 3z - 9
-2a = -8a - 3z - 9 - 5z
-2a + 8a = -3z - 9 - 5z
6a = -8z - 9
a = \( \frac{-8z - 9}{6} \)
a = \( \frac{-8z}{6} \) + \( \frac{-9}{6} \)
a = -1\(\frac{1}{3}\)z - 1\(\frac{1}{2}\)
Simplify (2a)(9ab) + (8a2)(4b).
| 132ab2 | |
| -14a2b | |
| 14a2b | |
| 50a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(2a)(9ab) + (8a2)(4b)
(2 x 9)(a x a x b) + (8 x 4)(a2 x b)
(18)(a1+1 x b) + (32)(a2b)
18a2b + 32a2b
50a2b