ASVAB Math Knowledge Practice Test 140446

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5c + 5c = -9c + 4z - 2 for c in terms of z.

\(\frac{3}{7}\)z + \(\frac{5}{7}\)
-\(\frac{1}{14}\)z - \(\frac{1}{7}\)
-6z + 8
-6\(\frac{1}{2}\)z + 2\(\frac{1}{2}\)