ASVAB Math Knowledge Practice Test 142196

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3b - 9b = 7b - 3z + 5 for b in terms of z.

\(\frac{1}{4}\)z + \(\frac{2}{3}\)
-1\(\frac{1}{2}\)z - 1\(\frac{1}{4}\)
\(\frac{1}{3}\)z - \(\frac{1}{5}\)
z + 6