When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8b - 4b = -8b - 5z - 1 for b in terms of z.
| -\(\frac{1}{2}\)z + 1\(\frac{1}{2}\) | |
| 4z + 1 | |
| \(\frac{1}{4}\)z + 2\(\frac{1}{4}\) | |
| -\(\frac{1}{16}\)z - \(\frac{1}{16}\) |