| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.68 |
| Score | 0% | 54% |
If angle a = 70° and angle b = 36° what is the length of angle c?
| 100° | |
| 74° | |
| 60° | |
| 89° |
The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 70° - 36° = 74°
Solve for a:
a2 - 15a + 54 = 0
| 6 or 9 | |
| 5 or -1 | |
| 9 or 7 | |
| 4 or -8 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
a2 - 15a + 54 = 0
(a - 6)(a - 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 6) or (a - 9) must equal zero:
If (a - 6) = 0, a must equal 6
If (a - 9) = 0, a must equal 9
So the solution is that a = 6 or 9
If the length of AB equals the length of BD, point B __________ this line segment.
trisects |
|
bisects |
|
intersects |
|
midpoints |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
If the base of this triangle is 9 and the height is 4, what is the area?
| 20 | |
| 44 | |
| 65 | |
| 18 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 9 x 4 = \( \frac{36}{2} \) = 18
Solve -3b - 6b = 4b - 3z + 7 for b in terms of z.
| -\(\frac{3}{7}\)z - 1 | |
| -19z + 3 | |
| \(\frac{7}{10}\)z + \(\frac{1}{10}\) | |
| -1\(\frac{1}{4}\)z - 1 |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-3b - 6z = 4b - 3z + 7
-3b = 4b - 3z + 7 + 6z
-3b - 4b = -3z + 7 + 6z
-7b = 3z + 7
b = \( \frac{3z + 7}{-7} \)
b = \( \frac{3z}{-7} \) + \( \frac{7}{-7} \)
b = -\(\frac{3}{7}\)z - 1