ASVAB Math Knowledge Practice Test 143613

Question 5 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -2a - 4a = -5a - 4y - 3 for a in terms of y.

3\(\frac{1}{5}\)y - \(\frac{1}{5}\)
y - 1
-1\(\frac{5}{8}\)y + \(\frac{1}{4}\)
\(\frac{1}{6}\)y + 1\(\frac{1}{3}\)