| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.71 |
| Score | 0% | 54% |
Order the following types of angle from least number of degrees to most number of degrees.
acute, right, obtuse |
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right, acute, obtuse |
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right, obtuse, acute |
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acute, obtuse, right |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
The dimensions of this cylinder are height (h) = 3 and radius (r) = 2. What is the surface area?
| 14π | |
| 80π | |
| 96π | |
| 20π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(22) + 2π(2 x 3)
sa = 2π(4) + 2π(6)
sa = (2 x 4)π + (2 x 6)π
sa = 8π + 12π
sa = 20π
Which of the following statements about math operations is incorrect?
all of these statements are correct |
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you can multiply monomials that have different variables and different exponents |
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you can add monomials that have the same variable and the same exponent |
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you can subtract monomials that have the same variable and the same exponent |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
Solve for c:
3c + 9 < \( \frac{c}{4} \)
| c < -\(\frac{24}{35}\) | |
| c < -3\(\frac{3}{11}\) | |
| c < 2 | |
| c < 1\(\frac{7}{65}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
3c + 9 < \( \frac{c}{4} \)
4 x (3c + 9) < c
(4 x 3c) + (4 x 9) < c
12c + 36 < c
12c + 36 - c < 0
12c - c < -36
11c < -36
c < \( \frac{-36}{11} \)
c < -3\(\frac{3}{11}\)
Solve 4b + 4b = -3b + 5x + 1 for b in terms of x.
| 6x - 1\(\frac{1}{2}\) | |
| -\(\frac{7}{12}\)x - \(\frac{1}{2}\) | |
| \(\frac{1}{7}\)x + \(\frac{1}{7}\) | |
| -4\(\frac{1}{2}\)x - \(\frac{1}{2}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
4b + 4x = -3b + 5x + 1
4b = -3b + 5x + 1 - 4x
4b + 3b = 5x + 1 - 4x
7b = x + 1
b = \( \frac{x + 1}{7} \)
b = \( \frac{x}{7} \) + \( \frac{1}{7} \)
b = \(\frac{1}{7}\)x + \(\frac{1}{7}\)