When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 4c = -3c - 7z - 3 for c in terms of z.
| -\(\frac{1}{2}\)z + 3 | |
| \(\frac{11}{12}\)z + \(\frac{1}{12}\) | |
| -1\(\frac{3}{8}\)z + 1 | |
| -1\(\frac{2}{9}\)z - \(\frac{1}{3}\) |