| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
Which of the following statements about math operations is incorrect?
you can add monomials that have the same variable and the same exponent |
|
you can subtract monomials that have the same variable and the same exponent |
|
you can multiply monomials that have different variables and different exponents |
|
all of these statements are correct |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
A quadrilateral is a shape with __________ sides.
4 |
|
2 |
|
5 |
|
3 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
Solve for b:
b2 - 12b + 13 = -4b - 2
| 5 or -1 | |
| 3 or 5 | |
| -4 or -9 | |
| -1 or -5 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
b2 - 12b + 13 = -4b - 2
b2 - 12b + 13 + 2 = -4b
b2 - 12b + 4b + 15 = 0
b2 - 8b + 15 = 0
Next, factor the quadratic equation:
b2 - 8b + 15 = 0
(b - 3)(b - 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 3) or (b - 5) must equal zero:
If (b - 3) = 0, b must equal 3
If (b - 5) = 0, b must equal 5
So the solution is that b = 3 or 5
Simplify (y - 6)(y + 5)
| y2 + 11y + 30 | |
| y2 - y - 30 | |
| y2 - 11y + 30 | |
| y2 + y - 30 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y - 6)(y + 5)
(y x y) + (y x 5) + (-6 x y) + (-6 x 5)
y2 + 5y - 6y - 30
y2 - y - 30
For this diagram, the Pythagorean theorem states that b2 = ?
c2 - a2 |
|
c2 + a2 |
|
a2 - c2 |
|
c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)