When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 5c = -6c + 6z - 9 for c in terms of z.
| \(\frac{3}{16}\)z - \(\frac{3}{16}\) | |
| 1\(\frac{2}{9}\)z - 1 | |
| 4\(\frac{1}{3}\)z + 2\(\frac{1}{3}\) | |
| -\(\frac{2}{3}\)z - \(\frac{1}{6}\) |