ASVAB Math Knowledge Practice Test 147638 Results

Your Results Global Average
Questions 5 5
Correct 0 2.77
Score 0% 55%

Review

1

Solve 6b - 8b = -5b + 5z - 4 for b in terms of z.

34% Answer Correctly
1\(\frac{2}{11}\)z - \(\frac{4}{11}\)
-\(\frac{1}{3}\)z + 1
-\(\frac{1}{3}\)z + \(\frac{8}{9}\)
-\(\frac{1}{2}\)z - \(\frac{1}{2}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

6b - 8z = -5b + 5z - 4
6b = -5b + 5z - 4 + 8z
6b + 5b = 5z - 4 + 8z
11b = 13z - 4
b = \( \frac{13z - 4}{11} \)
b = \( \frac{13z}{11} \) + \( \frac{-4}{11} \)
b = 1\(\frac{2}{11}\)z - \(\frac{4}{11}\)


2

The dimensions of this cylinder are height (h) = 5 and radius (r) = 7. What is the volume?

62% Answer Correctly
384π
144π
200π
245π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(72 x 5)
v = 245π


3

The dimensions of this trapezoid are a = 6, b = 6, c = 7, d = 5, and h = 4. What is the area?

51% Answer Correctly
36
22
22\(\frac{1}{2}\)
17

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(6 + 5)(4)
a = ½(11)(4)
a = ½(44) = \( \frac{44}{2} \)
a = 22


4

Order the following types of angle from least number of degrees to most number of degrees.

75% Answer Correctly

acute, obtuse, right

right, obtuse, acute

acute, right, obtuse

right, acute, obtuse


Solution

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.


5

A cylinder with a radius (r) and a height (h) has a surface area of:

54% Answer Correctly

4π r2

π r2h2

2(π r2) + 2π rh

π r2h


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.