| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.62 |
| Score | 0% | 52% |
To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?
Last |
|
Inside |
|
First |
|
Odd |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.
Solve for z:
-5z + 7 > \( \frac{z}{1} \)
| z > \(\frac{12}{47}\) | |
| z > -10\(\frac{4}{5}\) | |
| z > 1\(\frac{1}{6}\) | |
| z > -1\(\frac{1}{48}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-5z + 7 > \( \frac{z}{1} \)
1 x (-5z + 7) > z
(1 x -5z) + (1 x 7) > z
-5z + 7 > z
-5z + 7 - z > 0
-5z - z > -7
-6z > -7
z > \( \frac{-7}{-6} \)
z > 1\(\frac{1}{6}\)
On this circle, a line segment connecting point A to point D is called:
circumference |
|
diameter |
|
chord |
|
radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Factor y2 + 3y - 54
| (y + 6)(y - 9) | |
| (y - 6)(y + 9) | |
| (y - 6)(y - 9) | |
| (y + 6)(y + 9) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -54 as well and sum (Inside, Outside) to equal 3. For this problem, those two numbers are -6 and 9. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 3y - 54
y2 + (-6 + 9)y + (-6 x 9)
(y - 6)(y + 9)
Solve 9a + 9a = -3a + 5y + 6 for a in terms of y.
| \(\frac{9}{11}\)y - \(\frac{2}{11}\) | |
| -1\(\frac{1}{10}\)y - \(\frac{1}{10}\) | |
| -8\(\frac{1}{2}\)y - 1 | |
| -\(\frac{1}{3}\)y + \(\frac{1}{2}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
9a + 9y = -3a + 5y + 6
9a = -3a + 5y + 6 - 9y
9a + 3a = 5y + 6 - 9y
12a = -4y + 6
a = \( \frac{-4y + 6}{12} \)
a = \( \frac{-4y}{12} \) + \( \frac{6}{12} \)
a = -\(\frac{1}{3}\)y + \(\frac{1}{2}\)