ASVAB Math Knowledge Practice Test 148278 Results

Your Results Global Average
Questions 5 5
Correct 0 2.73
Score 0% 55%

Review

1

The endpoints of this line segment are at (-2, -6) and (2, 4). What is the slope-intercept equation for this line?

41% Answer Correctly
y = -2x - 3
y = 3x + 4
y = -2\(\frac{1}{2}\)x - 2
y = 2\(\frac{1}{2}\)x - 1

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -6) and (2, 4) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (-6.0)}{(2) - (-2)} \) = \( \frac{10}{4} \)
m = 2\(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = 2\(\frac{1}{2}\)x - 1


2

The formula for the area of a circle is which of the following?

24% Answer Correctly

c = π d

c = π r2

c = π d2

c = π r


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


3

If BD = 13 and AD = 19, AB = ?

75% Answer Correctly
2
6
13
9

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 19 - 13
AB = 6


4

Simplify (9a)(4ab) + (2a2)(9b).

65% Answer Correctly
54a2b
143ab2
54ab2
18a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(9a)(4ab) + (2a2)(9b)
(9 x 4)(a x a x b) + (2 x 9)(a2 x b)
(36)(a1+1 x b) + (18)(a2b)
36a2b + 18a2b
54a2b


5

If the area of this square is 36, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
8\( \sqrt{2} \)
7\( \sqrt{2} \)
6\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)