| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
Solve for x:
3x - 3 > \( \frac{x}{-4} \)
| x > \(\frac{18}{23}\) | |
| x > \(\frac{16}{31}\) | |
| x > 1\(\frac{13}{23}\) | |
| x > \(\frac{12}{13}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
3x - 3 > \( \frac{x}{-4} \)
-4 x (3x - 3) > x
(-4 x 3x) + (-4 x -3) > x
-12x + 12 > x
-12x + 12 - x > 0
-12x - x > -12
-13x > -12
x > \( \frac{-12}{-13} \)
x > \(\frac{12}{13}\)
What is 5a - 3a?
| 2a | |
| 8 | |
| a2 | |
| 2 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
5a - 3a = 2a
What is 6a + 3a?
| 9a | |
| 3 | |
| 18a | |
| 9 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
6a + 3a = 9a
For this diagram, the Pythagorean theorem states that b2 = ?
a2 - c2 |
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c - a |
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c2 - a2 |
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c2 + a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Which of the following statements about a triangle is not true?
perimeter = sum of side lengths |
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area = ½bh |
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sum of interior angles = 180° |
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exterior angle = sum of two adjacent interior angles |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.