| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.81 |
| Score | 0% | 56% |
If the length of AB equals the length of BD, point B __________ this line segment.
intersects |
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midpoints |
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trisects |
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bisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
Which of the following expressions contains exactly two terms?
polynomial |
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binomial |
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monomial |
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quadratic |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
The formula for the area of a circle is which of the following?
a = π r |
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a = π d |
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a = π r2 |
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a = π d2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Which of the following statements about parallel lines with a transversal is not correct?
same-side interior angles are complementary and equal each other |
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all of the angles formed by a transversal are called interior angles |
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all acute angles equal each other |
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angles in the same position on different parallel lines are called corresponding angles |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
Solve 7b + 4b = 9b + 8z + 1 for b in terms of z.
| \(\frac{13}{14}\)z + \(\frac{1}{14}\) | |
| \(\frac{6}{11}\)z - \(\frac{2}{11}\) | |
| z - 1\(\frac{1}{3}\) | |
| -2z - \(\frac{1}{2}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
7b + 4z = 9b + 8z + 1
7b = 9b + 8z + 1 - 4z
7b - 9b = 8z + 1 - 4z
-2b = 4z + 1
b = \( \frac{4z + 1}{-2} \)
b = \( \frac{4z}{-2} \) + \( \frac{1}{-2} \)
b = -2z - \(\frac{1}{2}\)