When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6b + 5b = 9b + 8z - 2 for b in terms of z.
| \(\frac{3}{5}\)z + 1\(\frac{4}{5}\) | |
| 1\(\frac{1}{5}\)z - 1\(\frac{1}{5}\) | |
| -\(\frac{1}{5}\)z + \(\frac{2}{15}\) | |
| -15z - 4 |