When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c - 2c = -2c - 6z - 4 for c in terms of z.
| -\(\frac{4}{7}\)z - \(\frac{4}{7}\) | |
| \(\frac{2}{5}\)z + \(\frac{3}{5}\) | |
| \(\frac{7}{8}\)z + \(\frac{3}{8}\) | |
| \(\frac{1}{12}\)z + \(\frac{1}{2}\) |