ASVAB Math Knowledge Practice Test 15112 Results

Your Results Global Average
Questions 5 5
Correct 0 3.72
Score 0% 74%

Review

1

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

67% Answer Correctly

2lw x 2wh + 2lh

h x l x w

lw x wh + lh

h2 x l2 x w2


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.


2

What is 7a + 3a?

81% Answer Correctly
21a2
10a
10
4

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

7a + 3a = 10a


3

On this circle, line segment AB is the:

70% Answer Correctly

diameter

circumference

radius

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

Simplify 4a x 8b.

85% Answer Correctly
12ab
32ab
32\( \frac{b}{a} \)
32a2b2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

4a x 8b = (4 x 8) (a x b) = 32ab


5

If the area of this square is 36, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
8\( \sqrt{2} \)
7\( \sqrt{2} \)
6\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)