| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.74 |
| Score | 0% | 55% |
Which of the following statements about parallel lines with a transversal is not correct?
same-side interior angles are complementary and equal each other |
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all of the angles formed by a transversal are called interior angles |
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angles in the same position on different parallel lines are called corresponding angles |
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all acute angles equal each other |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
Breaking apart a quadratic expression into a pair of binomials is called:
factoring |
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deconstructing |
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normalizing |
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squaring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Simplify (7a)(7ab) + (2a2)(9b).
| -31a2b | |
| 154a2b | |
| -31ab2 | |
| 67a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(7ab) + (2a2)(9b)
(7 x 7)(a x a x b) + (2 x 9)(a2 x b)
(49)(a1+1 x b) + (18)(a2b)
49a2b + 18a2b
67a2b
Solve for a:
a2 - 9a + 31 = 2a + 1
| 5 or 6 | |
| -4 or -5 | |
| 4 or -8 | |
| 5 or -6 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
a2 - 9a + 31 = 2a + 1
a2 - 9a + 31 - 1 = 2a
a2 - 9a - 2a + 30 = 0
a2 - 11a + 30 = 0
Next, factor the quadratic equation:
a2 - 11a + 30 = 0
(a - 5)(a - 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 5) or (a - 6) must equal zero:
If (a - 5) = 0, a must equal 5
If (a - 6) = 0, a must equal 6
So the solution is that a = 5 or 6
The dimensions of this cylinder are height (h) = 4 and radius (r) = 6. What is the surface area?
| 16π | |
| 198π | |
| 120π | |
| 208π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(62) + 2π(6 x 4)
sa = 2π(36) + 2π(24)
sa = (2 x 36)π + (2 x 24)π
sa = 72π + 48π
sa = 120π