ASVAB Math Knowledge Practice Test 152905 Results

Your Results Global Average
Questions 5 5
Correct 0 2.74
Score 0% 55%

Review

1

Which of the following statements about parallel lines with a transversal is not correct?

36% Answer Correctly

same-side interior angles are complementary and equal each other

all of the angles formed by a transversal are called interior angles

angles in the same position on different parallel lines are called corresponding angles

all acute angles equal each other


Solution

Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).


2

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

factoring

deconstructing

normalizing

squaring


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


3

Simplify (7a)(7ab) + (2a2)(9b).

65% Answer Correctly
-31a2b
154a2b
-31ab2
67a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(7a)(7ab) + (2a2)(9b)
(7 x 7)(a x a x b) + (2 x 9)(a2 x b)
(49)(a1+1 x b) + (18)(a2b)
49a2b + 18a2b
67a2b


4

Solve for a:
a2 - 9a + 31 = 2a + 1

48% Answer Correctly
5 or 6
-4 or -5
4 or -8
5 or -6

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

a2 - 9a + 31 = 2a + 1
a2 - 9a + 31 - 1 = 2a
a2 - 9a - 2a + 30 = 0
a2 - 11a + 30 = 0

Next, factor the quadratic equation:

a2 - 11a + 30 = 0
(a - 5)(a - 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 5) or (a - 6) must equal zero:

If (a - 5) = 0, a must equal 5
If (a - 6) = 0, a must equal 6

So the solution is that a = 5 or 6


5

The dimensions of this cylinder are height (h) = 4 and radius (r) = 6. What is the surface area?

48% Answer Correctly
16π
198π
120π
208π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(62) + 2π(6 x 4)
sa = 2π(36) + 2π(24)
sa = (2 x 36)π + (2 x 24)π
sa = 72π + 48π
sa = 120π