When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 4c = -5c + y + 3 for c in terms of y.
| -\(\frac{1}{2}\)y + \(\frac{1}{2}\) | |
| 1\(\frac{2}{9}\)y - \(\frac{2}{3}\) | |
| y - 6 | |
| \(\frac{5}{8}\)y + \(\frac{3}{8}\) |