When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c - 4c = -3c - 2z + 6 for c in terms of z.
| -\(\frac{2}{5}\)z - 1\(\frac{1}{5}\) | |
| -\(\frac{3}{7}\)z - \(\frac{9}{14}\) | |
| \(\frac{4}{5}\)z - \(\frac{4}{5}\) | |
| z + 4\(\frac{1}{2}\) |