When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c - 4c = 4c + 2y + 8 for c in terms of y.
| y + 4 | |
| 6y + 8 | |
| -\(\frac{1}{2}\)y + \(\frac{3}{4}\) | |
| y - \(\frac{1}{3}\) |