When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -c - 8c = 2c + 5y + 1 for c in terms of y.
| -4\(\frac{1}{3}\)y - \(\frac{1}{3}\) | |
| \(\frac{1}{2}\)y + \(\frac{1}{6}\) | |
| -8y + 3\(\frac{1}{2}\) | |
| \(\frac{5}{11}\)y + \(\frac{5}{11}\) |