| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.09 |
| Score | 0% | 62% |
Solve for y:
y2 + 8y + 12 = 0
| -1 or -3 | |
| 4 or 1 | |
| 6 or -4 | |
| -2 or -6 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
y2 + 8y + 12 = 0
(y + 2)(y + 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 2) or (y + 6) must equal zero:
If (y + 2) = 0, y must equal -2
If (y + 6) = 0, y must equal -6
So the solution is that y = -2 or -6
The dimensions of this cylinder are height (h) = 6 and radius (r) = 1. What is the volume?
| 343π | |
| 648π | |
| 6π | |
| 512π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(12 x 6)
v = 6π
Which of the following statements about a triangle is not true?
exterior angle = sum of two adjacent interior angles |
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perimeter = sum of side lengths |
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sum of interior angles = 180° |
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area = ½bh |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
If the area of this square is 36, what is the length of one of the diagonals?
| 8\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)
Simplify (8a)(2ab) - (7a2)(4b).
| 110ab2 | |
| 44a2b | |
| -12a2b | |
| 12ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(8a)(2ab) - (7a2)(4b)
(8 x 2)(a x a x b) - (7 x 4)(a2 x b)
(16)(a1+1 x b) - (28)(a2b)
16a2b - 28a2b
-12a2b