ASVAB Math Knowledge Practice Test 158003 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

A trapezoid is a quadrilateral with one set of __________ sides.

70% Answer Correctly

equal length

equal angle

right angle

parallel


Solution

A trapezoid is a quadrilateral with one set of parallel sides.


2

Solve for z:
z2 - 2z - 8 = 0

58% Answer Correctly
7 or -3
-2 or 4
3 or -8
6 or 1

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

z2 - 2z - 8 = 0
(z + 2)(z - 4) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 2) or (z - 4) must equal zero:

If (z + 2) = 0, z must equal -2
If (z - 4) = 0, z must equal 4

So the solution is that z = -2 or 4


3

A right angle measures:

90% Answer Correctly

180°

45°

360°

90°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


4

If the area of this square is 81, what is the length of one of the diagonals?

68% Answer Correctly
3\( \sqrt{2} \)
9\( \sqrt{2} \)
4\( \sqrt{2} \)
6\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)


5

Solve for x:
-2x + 8 = \( \frac{x}{9} \)

46% Answer Correctly
2\(\frac{2}{9}\)
3\(\frac{15}{19}\)
-\(\frac{3}{5}\)
2\(\frac{2}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-2x + 8 = \( \frac{x}{9} \)
9 x (-2x + 8) = x
(9 x -2x) + (9 x 8) = x
-18x + 72 = x
-18x + 72 - x = 0
-18x - x = -72
-19x = -72
x = \( \frac{-72}{-19} \)
x = 3\(\frac{15}{19}\)