ASVAB Math Knowledge Practice Test 158817

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4a - 4a = 7a + 6z + 2 for a in terms of z.

-\(\frac{1}{6}\)z - \(\frac{1}{6}\)
-\(\frac{7}{9}\)z - \(\frac{2}{3}\)
-1\(\frac{1}{2}\)z + \(\frac{1}{2}\)
-3\(\frac{1}{3}\)z - \(\frac{2}{3}\)