ASVAB Math Knowledge Practice Test 161706

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a + a = 2a - 5x - 2 for a in terms of x.

1\(\frac{1}{3}\)x - 1\(\frac{1}{3}\)
1\(\frac{1}{4}\)x - \(\frac{2}{3}\)
-1\(\frac{1}{2}\)x - \(\frac{1}{2}\)
-\(\frac{5}{17}\)x + \(\frac{7}{17}\)