| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.86 |
| Score | 0% | 57% |
Which of the following expressions contains exactly two terms?
binomial |
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quadratic |
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monomial |
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polynomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
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4π r2 |
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2(π r2) + 2π rh |
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π r2h2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
The endpoints of this line segment are at (-2, 7) and (2, -1). What is the slope of this line?
| -2 | |
| 2 | |
| -3 | |
| -2\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 7) and (2, -1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-1.0) - (7.0)}{(2) - (-2)} \) = \( \frac{-8}{4} \)If the area of this square is 4, what is the length of one of the diagonals?
| 2\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| \( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)
Solve -7c - 6c = -5c + 5y + 6 for c in terms of y.
| 2y - 2\(\frac{1}{3}\) | |
| \(\frac{4}{13}\)y - \(\frac{9}{13}\) | |
| -5\(\frac{1}{2}\)y - 3 | |
| y - 2\(\frac{1}{2}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-7c - 6y = -5c + 5y + 6
-7c = -5c + 5y + 6 + 6y
-7c + 5c = 5y + 6 + 6y
-2c = 11y + 6
c = \( \frac{11y + 6}{-2} \)
c = \( \frac{11y}{-2} \) + \( \frac{6}{-2} \)
c = -5\(\frac{1}{2}\)y - 3