When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 5c = 9c + 6x + 8 for c in terms of x.
| -1\(\frac{5}{6}\)x - 1\(\frac{1}{3}\) | |
| 8x - 1 | |
| \(\frac{3}{4}\)x - \(\frac{1}{4}\) | |
| 7x + 7 |