ASVAB Math Knowledge Practice Test 162141 Results

Your Results Global Average
Questions 5 5
Correct 0 3.16
Score 0% 63%

Review

1

The endpoints of this line segment are at (-2, 1) and (2, -5). What is the slope-intercept equation for this line?

41% Answer Correctly
y = -1\(\frac{1}{2}\)x - 2
y = -1\(\frac{1}{2}\)x + 4
y = 2\(\frac{1}{2}\)x + 4
y = 2x + 4

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, -5) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-5.0) - (1.0)}{(2) - (-2)} \) = \( \frac{-6}{4} \)
m = -1\(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = -1\(\frac{1}{2}\)x - 2


2

Solve for y:
-6y + 1 = -5 - y

59% Answer Correctly
1
1\(\frac{2}{3}\)
\(\frac{1}{5}\)
1\(\frac{1}{5}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-6y + 1 = -5 - y
-6y = -5 - y - 1
-6y + y = -5 - 1
-5y = -6
y = \( \frac{-6}{-5} \)
y = 1\(\frac{1}{5}\)


3

What is 2a8 - 6a8?

74% Answer Correctly
8
12a8
-4a8
-4a16

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

2a8 - 6a8 = -4a8


4

Breaking apart a quadratic expression into a pair of binomials is called:

75% Answer Correctly

normalizing

squaring

deconstructing

factoring


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


5

Simplify (7a)(7ab) + (3a2)(4b).

65% Answer Correctly
37a2b
37ab2
61a2b
98a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(7a)(7ab) + (3a2)(4b)
(7 x 7)(a x a x b) + (3 x 4)(a2 x b)
(49)(a1+1 x b) + (12)(a2b)
49a2b + 12a2b
61a2b