When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c + 3c = 3c - 2z + 5 for c in terms of z.
| -z + \(\frac{1}{2}\) | |
| -\(\frac{1}{6}\)z + \(\frac{1}{2}\) | |
| \(\frac{13}{15}\)z + \(\frac{2}{15}\) | |
| \(\frac{5}{8}\)z - \(\frac{5}{8}\) |