ASVAB Math Knowledge Practice Test 164961

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -c - 9c = 5c - 4x - 9 for c in terms of x.

\(\frac{1}{4}\)x - \(\frac{3}{4}\)
-\(\frac{5}{6}\)x + 1\(\frac{1}{2}\)
\(\frac{5}{6}\)x + \(\frac{2}{3}\)
1\(\frac{2}{3}\)x - 2\(\frac{2}{3}\)